What will be the output of the given program?
#include<stdio.h>
void main()
{
   int a=11,b=5;
   if(a=5) b++;
   printf("%d %d", ++a, b++);
}
a)
12 7
b)
5 6
c)
6 6
d)
6 7
Correct answer is option 'C'. Can you explain this answer?

Question

What will be the output of the given program?

#include<stdio.h>
void main()
{
   int a=11,b=5;
   if(a=5) b++;
   printf("%d %d", ++a, b++);
}

a)
12 7
b)
5 6
c)
6 6
d)
6 7

Correct answer is option 'C'. Can you explain this answer?

Answer

Here if condition evaluates to true as a non-zero value i.e 5 is assigned to a.
So the value of a = 5 and after increment value of b = 6.
In printf statement due to pre-increment of a value of a printed will be 6 and due to post-increment of b value of b printed will be 6 and not 7.

Answer

Explanation:

Initial values:
- a = 11
- b = 5

Condition in if statement:
- The condition in the if statement is (a=5).
- Here, a is assigned the value 5 (a=5) which is a non-zero value, so the condition will be true.
- As a result, the code inside the if statement will be executed.

Code inside the if statement:
- Inside the if statement, b will be incremented by 1 (b++). So, b will become 6.

Output:
- After the if statement, a will be incremented by 1 (++a). So, a will become 12.
- The value of b will be incremented by 1 as well (b++). So, b will become 7.
Therefore, the output of the program will be:

6 6

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